Python 对目录的操作

共计 1249 个字符，预计需要花费 4 分钟才能阅读完成。

一、递归遍历目录

# 返回所有文件的绝对路径 
def traverseDir(dirPath):
    absPathList = []
    import os

    filesList = os.listdir(dirPath)
    for fileName in filesList:
        absPath = os.path.join(dirPath, fileName)
        if os.path.isdir(absPath):
            # 目录 
            absPathList += traverseDir(absPath)
        else:
            # 文件 
            # print(absPath)
            absPathList.append(absPath)
    return absPathList

absPathList = traverseDir(r"C:\Users\sunck\Desktop\file")
print(absPathList)
print(len(absPathList))
# for absPath in absPathList:
#     print(absPath)

二、栈模拟递归遍历目录

def traverseDir(dirPath):
    import os
    absPathList = []
    myStack = []
    myStack.append(dirPath)

    while len(myStack) != 0:
        path = myStack.pop()

        fileList = os.listdir(path)
        for fileName in fileList:
            absPath = os.path.join(path, fileName)
            if os.path.isdir(absPath):
                myStack.append(absPath)
            else:
                absPathList.append(absPath)
    return absPathList


absPathList = traverseDir(r"C:\Users\sunck\Desktop\file")
print(absPathList)
print(len(absPathList))

三、队列模拟递归遍历目录

def traverseDir(dirPath):
    import os
    from collections import deque
    absPathList = []

    q = deque([])
    q.append(dirPath)

    while len(q) != 0:
        path = q.popleft()

        fileList = os.listdir(path)
        for fileName in fileList:
            absPath = os.path.join(path, fileName)
            if os.path.isdir(absPath):
                q.append(absPath)
            else:
                absPathList.append(absPath)
                # yield absPath
    return absPathList

absPathList = traverseDir(r"C:\Users\sunck\Desktop\file")
print(absPathList)
print(len(absPathList))